4t^2+16=1+4t+6

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Solution for 4t^2+16=1+4t+6 equation: 



4t^2+16=1+4t+6

We move all terms to the left:

4t^2+16-(1+4t+6)=0

We add all the numbers together, and all the variables

4t^2-(4t+7)+16=0

We get rid of parentheses

4t^2-4t-7+16=0

We add all the numbers together, and all the variables

4t^2-4t+9=0

a = 4; b = -4; c = +9;
Δ = b2-4ac
Δ = -42-4·4·9
Δ = -128
Delta is less than zero, so there is no solution for the equation

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